Roulette : How to Win
Jimmy Jordan

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VERY NEAR THE INFALLIBLE METHOD for roulette strategy.

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This book is directed to the player of roulette. To the player that knows already basically

the operation of the game. To the player that has proven other methods without success.

And lack to him two very important things, a book that explain to him that what happens

really in the roulette, and a roulette strategy that to give him some high guarantees of success in the

game.

All we have read some book that fills pages and more pages on the theories of the random

and the probabilities calculation without a subsequent practical application, and also we

have proven methods "miraculous" that though make to win money when the situation is

favorable do not notify of the dangers of an unfavorable situation, neither explain how

surpassing it. These situations are presented more often than what we think and we wish.

Precisely by these reasons I will not extend in theoretical explanations. I will limit me to

explain some indispensable basic notions to understand on that base has been built the

method and below we will put in practice its game mechanism on real game sequences.

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What are the figures?. For the purpose of the simple combinations of the roulette, a

number anyone can be PAR or ODD, LACK or PASSES, RED or BLACK. We will center

in this last combination.

We have two columns to note the combination of each play. If the number is red we make

an annotation in the cabin of the left and if it is black in the right cabin. Each play can

have an alone annotation, or to the right or to the left, and it is one of the two possible

alternatives: RED or BLACK. It is said that the possible figures of 1 (of one play) are 2.

In the second consecutive play the possibilities are: RED - RED, RED -BLACK, BLACK -

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RED, BLACK - BLACK, and is said that the figures of 2 are 4. In 3 consecutive plays the

possibilities are 8 (fig. 1).

GRAPHIC

1

The possibility of the fact that is formed a figure of 3 (1 between 8) is the half of be formed

a figure of 2 (1 between 4) and the fourth part that a figure of 1 (1 between 2). Is the same

as to say:

So that could be formed one figure of 2 those of 1 will have been able to form 2 times each

one, and so that could be formed one figure of 3 those of 2 will have been able to form also

2 times, and thus successive. For so much, we can say that the figures of 1 are the double

that those of 2, the figures of 2 are the double that those of 3, the figures of 3 are the double

that those of 4, the figures of 4 are the double that those of 5, etc.

This reasoning can be applied to the series saying that the series of 1 are the double that

those of 2, the series of 2 are the double that those of 3, the series of 3 are the double that

those of 4, etc.

Evidently this ideal distribution is not fulfilled, and we can only assert is that while goes

increasing the number of plays, the distribution will be gone approximating every time more

to this ideal distribution. It can be that never it is fulfilled exactly, but the difference

between the percentage that would correspond to every series taking into account the

number of plays and the real will be every time smaller.

The ideal roulette strategy distribution of the series in 247 plays would be this:

1 series of 7 = 7 plays 0.78

2 series of 6 = 12 plays 1.57

4 series of 5. = 20 " 3.15

8 series of 4. = 32 " 6.30

16 series of 3. = 48 " 12.59

32 series of 2. = 64 " 25.19

64 series of 1. = 64 " 50.39

TOTAL 127 series. 247 plays. 100.00

If we go increasing the number of plays the corresponding percentage to the series of 1 goes

approximating to 50%, that of the series of 2 to 25%, that of the series of 3 to 12,5%, etc.

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In the book "THE COMPLETE BOOK OF CASINO GAMES" the authors explain a

If the first play is BLACK, in the following one you bet 1 chip on the break of the series,

that is to say, on RED. If the second play is RED you win 1 chip and you restart betting 1

chip on BLACK.

1 0

2 1 1 1

If the second play has not been RED but BLACK, you bet 3 chips on RED. If the third play

is RED you get 2 chips (3 won minus 1 lost in the first play) and you restart betting 1 chip

on BLACK.

1 0

2 1 -1 -1

3 3 3 2

If the third play has been BLACK you bet 7 chips on RED. If the fourth play is RED you

get 3 chips (7 won minus 4 lost) and you restart betting 1 chip on BLACK.

1 0

2 1 -1 -1

3 3 -3 -4

4 7 7 3

If the fourth play is BLACK, you don’t bet more on the break of the series. We’ve had a

series of 4. The system expects a series of 7, that is to say, 3 more BLACK. So far the losses

amount to 11 units, divided into 3 bets (4, 4 and 3).

1 0

2 1 -1 -1

3 3 -3 -4

4 7 -7 -11

Fifth play: you bet the first 4 units on BLACK. If the fifth play is in fact a BLACK, you

bet the following 4 units on BLACK in the sixth play. If you also win then you bet the last

3 units on BLACK in the seventh play. If the game has gone by in this manner you have

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obtained as net profits all the ones originated by the series of 1, of 2 and of 3 that have

appeared until then in this roulette strategy.

1 0

2 1 -1 -1

3 3 -3 -4

4 7 -7 -11

5 4 4 -7

6 4 4 -3

7 3 3 0

However, when one of the recovery bets of the plays 5, 6 or 7 fails, this loss is added to the

one which still has to be recovered and we restart the cycle betting a unit on the

intermittence, 3 units on the break of the series of 2 and 7 on the break of the series of 3,

until a series of 4 appears again.

1

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2 1 -1 -1

3 3 -3 -4

4 7 -7 -11 11 4 4 3

5 4 -4 -15 15

1

2 1 -1 -1

3 3 -3 -4

4 7 -7 -11 11 4 4 3

5 4 4 -7 7 4 3 0

6 4 -4 -11 11

1

2 1 -1 -1

3 3 -3 -4

4 7 -7 -11 11 4 4 3

5 4 4 -7 7 4 3 0

6 4 4 -3 3 3 0 0

7 3 -3 -6 6

An example, the game goes by with the profits obtained with the series from 1, 2 and 3 until

a series of 4 appears. The loss amounts to 11 units. In the following play you bet 4 chips

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on the formation of a series of 5 and you lost. These 4 chips are added to the previous 11

that amount to a total of 15. The cycle restarts, until a series of 4 appears that will entail

another loss of 11 units. This loss will have to be added to the already existing of 15,

amounting a total of 26, that will be divided in 3 (9, 9 and 8). In the fifth play we would

bet 9 chips on the continuation of the strategy series.

1

2 1 1 1

3 1 -1 0

4 3 3 3

5 1 1 4

6 1 1 5

7 1 1 6

8 1 -1 5

9 3 -3 2

10 7 7 9

11 1 1 10

12 1 -1 9

13 3 3 12

14 1 -1 11

15 3 3 14

16 1 1 15

17 1 -1 14

18 3 -3 11

19 7 -7 4 -11 4 4 3

20 4 -4 0 -15

21 1 1 1

22 1 1 2

23 1 -1 1

24 3 -3 -2

25 7 -7 -9 -26 9 9 8

26 9 9 0 17 9 8 0

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27 9 9 9 8 8 0 0

28 8 8 17 0 0 0 0

29

As we can see, all the strategy is based on the appearance of a series of 7 or higher. We

know that a series of 7 has a possibility of being formed every 247 plays and we have seen

that in a sufficiently large number of plays this prediction is true. But, obviously, this fact

does not occur regularly in roulette and in the same way that we can have 3 series of more than 6 in a

sequence of 30 plays, we can also find ourselves having to wait 300 plays until one

appears. What are the average losses that you may have to assume waiting for the series of

7?

Working always on the ideal distribution that we know and taking into account that a series

of 4 causes that the deficit increases in 11 units more the third part of the already existing

one, that a series of 5 does not alter the deficit and that a series of 6 reduces it 2/3 parts, we

have to assume losses of around 330 chips with recovery bets of 110. The deficit is not

really real since we would have been collecting the profits obtained with the appearance of

the series from 1, 2 and 3, and they would be exactly 176 units. Summarising, we would

have an effective deficit of 154 chips and to recover we would have to make bets of 110.

All this supposing that every two series of 4 it appears one of 5, and for every two series of

5, one of 6. What does this system require to put it into practice? Two principal

requirements, first to have a great capital and second to have nerves of steel to apply it in

the game table with real money. But neither of these two requirements would be enough to

guarantee the usefulness of the system. The time could arrive, and in fact we have seen it

ourselves several times during the tests we made, where the recovery bets surpassed the

maximum bet allowed by the table (540 times the minimal bet). And we have also to take

into account the appearance of the zero. This factor is the more important the higher the

quantities which we can be forced to bet following the system.

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2 OBSERVATIONS:

1) It is a very risky system one that bases all the recovery on a fact that occurs once every

247 plays.

2) Setting aside its mathematical possibilities, the system was not making the most of the

appearance of the series of 1, 2 and 3. García obtained 1 chip of profit with the series of 1,

2 chips with the series of 2 and 3 chips with the series of 3. But if we apply the progression

3 - 5 - 9, the series of one would produce 3 chips of profit, the series of 2 two, and the series

of three 1 chip. The loss caused by a series of 4 would be of 17 units instead of 11.

Obviously, the deficit would increase more quickly, but the system is based on recovering

all the losses with the first series of 7 or higher. When the series appears, after the usual 247

plays, the profits obtained with Garcia’s system with the series of 1, 2 and 3 are of 176 units

and with our progression they would amount to 272.

1

2 1 1 1

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3 1 -1 0

4 3 3 3

5 1 1 4

6 1 1 5

7 1 1 6

8 1 -1 5

9 3 3 8

10 1 -1 7

11 3 3 10

12 1 1 11

13 1 -1 10

14 3 -3 7

15 7 7 14

16 1 1 15

17 1 -1 14

18 3 3 17

19 1 -1 16

20 3 -3 13

21 7 7 20

22 1 1 21

23 1 1 22

24 1 1 23

25 1 -1 22

26 3 3 25

27 1 -1 24

28 3 3 27

29 1 1 28

30 1 1 29

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1

2 3 3 3

3 3 -3 0

4 5 5 5

5 3 3 8

6 3 3 11

7 3 3 14

8 3 -3 11

9 5 5 16

10 3 -3 13

11 5 5 18

12 3 3 21

13 3 -3 18

14 5 -5 13

15 9 9 22

16 3 3 25

17 3 -3 22

18 5 5 27

19 3 -3 24

20 5 -5 19

21 9 9 28

22 3 3 31

23 3 3 34

24 3 3 37

25 3 -3 40

26 5 5 45

27 3 -3 42

28 5 5 47

29 3 3 50

30 3 3 53

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This is GARCIA’s method. It was necessary to explain it to understand from which starting

point we have departed to arrive at the results that, as we will see, do guarantee the success

in a percentage near to 100% of the cases and do give us security during the game in

comparison to the other class of violent game that guarantees only occasionally this

recovery.

To begin with, we will say that if we have to apply a system that bases the recovery of all

the losses on a specific fact, we prefer that this fact has more possibilities of appearing than

those which had the previous one and that were between 1 and 247.

We pay attention again to the ideal distribution of the series in 247 plays, but now

especially in the series of 1. There are 64, but which is their distribution throughout 247

plays? A series does not appear once every 4 plays, neither do appear the 64 together.

Applying the theory of the figures we can begin to know which would be the ideal

distribution of these 64 series.

When a series of 1 appears, there is a 50% possibilities that another series of one follows

and a 50% possibilities that any other series follows (2 , 3, 4, 5, etc.).

When two consecutive series of 1 appear, there is a 50% possibilities that another series of 1

follows and a 50% possibilities that any other series follows.

When three consecutive series of 1 appear, there is a 50% of possibilities that another series

of 1 appears and a 50% possibilities that any other series follows

And so on....

If we apply this on 64 series we obtain an ideal distribution in approximate groups that

would remain like this:

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TOTAL: 57 series.

We still have 7 series of 1 left to arrive at the total of 64. If we distributed them following

the calculation of probabilities, we could have the following distribution:

TOTAL: 64 series.

We have added two to the groups of 1, one to the groups of 2, and another to the groups of

3. What we want to know now is what right of appearance has every one of these groups in

the course of 247 plays. This point is easy to verify dividing the total number of plays by

the quantities of appearance of every type of group. These are the results:

García’s system tried to recover the losses with 3 consecutive bets in the 5th, 6th and 7th

plays of a series of 7. The number of series of a given length is equal to the sum of all

those of a higher length. This is the same as saying that the series of 1 are in opposition to

all the series of 2, 3, 4, 5, etc. together. We will take advantage of this information that the

calculation of probabilities gives us to put it into practice in the following way:

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report us 1 chip of profit.

of 3, 4 and 5.

1.

But if a group of 2 is valid, it is also valid one higher than 2. If we add all the groups of 2

and higher there is a total of 17 groups that should be used throughout the game to cancel

the deficit and leave as net profits the ones produced by all the series of 2, 3 and 4.

A group of 2 consecutive series of 1 or higher can appear every 15 plays. We have already

obtained a great advantage, as we do not have to wait for one chance every 247 plays to

cancel the deficit; in fact, during the game we will be able to cancel it on average 17 times.

This fact, as we will see in the practical demonstration, makes both the losses and the

recovery bets more reasonable in comparison to García’s system and give us more security

during the game.

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1

2

3 1 1 1

the 3rd play.

1

2

3 1 -1 -1

4 1 1 0

2 units in the 3rd and 4th plays.

1

2

3 1 -1 -1

4 1 -1 -2

5 1 1 -1

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3rd, 4th and 5th plays..

1

2

3 1 -1 -1

4 1 -1 -2

5 1 -1 -3

6 0

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1

2 0

3 0

4 1 -1 -1 1 1 0

5 1 1 0 1 1 0

6 1 1 1 0 0 0

7 0 0 1

8 1 -1 0 1 1 0

9 1 -1 -1 2 1 1

10 1 1 0 2 1 1

11 1 -1 -1 3 2 1

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12 1 1 0 3 2 1

13 2 2 2 1 1 0

14 1 -1 1 2 1 1

15 1 -1 0 3 2 1

16 1 1 1 3 2 1

17 2 -2 -1 5 3 2

18 1 1 0 5 3 2

19 3 3 3 2 2 0

21 0

22

The mechanics of the game may seem complicated. But it will not seem so, once you see

them in practice, in a real sequence. At the same time we will see how the game control

sheets have to be.

When the zero appears. we can mark the box in which it has appeared, if this interests us for

statistical effects; the play will be considered void to the purposes of the game, but we can

not assume the loss and put it in the bank of deficit to recover, since this would alter

enormously our predictions. The loss caused by zero will be half the bet made, and in the

following play the same bet will be made. Since we can not include this loss with the

general ones caused by the series of 3, 4 and 5, we will have to count it subtracting it from

the total profits.

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1 19 0 0

20 8 1 1 0 0 0 0

21 16 0 0 0 0 0

22 36 0 0 0 0 0

23 15 1 1 0 0 0

24 6 0 0 0 0 0

25 22 1 -1 -1 1 0

26 12 1 1 -1 1 0

27 30 1 -1 -2 1 1

28 32 1 -1 -3 2 1

29 12 1 -1 -4 2 2

30 15 1 1 -4 2 2

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31 19 2 2 -2 2 0

32 21 2 -2 -4 2 2

33 28 1 1 -4 2 2

34 24 2 -2 -6 3 3

35 31 1 -1 -7 4 3

39 8 5 5 -4 4 0

40 12 4 4 0 0 0

(produced by a series of 2).

We write the loss in the DEFICIT box, and as it is not possible to divide it into 2, we write a

1 in the box BETS 1 and a 0 in the box BETS 2.

directly to PROFITS. The deficit continues the same.

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recovery bet (BET 1) on the intermittence and we lose. The lost chip is added to the

previous deficit and is split into 2 recovery bets (1 and 1).

PROFITS directly.

on the intermittence and we win. We subtract it from the deficit and there is still a second

recovery of 1 left.

becomes again of 2.

it is divided into 2.

We have to wait again until the first intermittence occurs; that will be the sign to reactivate

the bets.

recovery bet of the deficit.

the PROFITS column there are reflected the chips won that are equal to the total of series of

2, 3 and 4 appeared in the sequence.

column and we update PROFITS. In the following play (it would have been 21, but for us it

is 20 again) we make again the bets that the system tells, making the relevant operations.

bet and the deficit is cancelled. As net PROFITS we obtain 7.5 units, 8 for the total from

the series of 2, 3 and 4 appeared, minus the loss produced by the appearance of the zero in

the play 20.

COMMENTARIES:

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1) We can see in the play 37 that the recovery deficit indicates - 9 and in reality it is of - 1.5

units.

2) The isolated series of 1 do not alter the deficit and in some phases of the game they

allow us to cancel it (when we have only pending recovery bet).

3) The bets are relatively lower in comparison with the GARCIA’s system.

4) The yield of the system, as long as you closed all the recoveries, it is the sum of all the

series of 2, 3 and 4 minus the losses produced by the zeroes (approximately of one chip

every 5 plays).

So far the theory has been explained. What the reader, and potential player is interested in

knowing is which practical possibilities has the system.

Now we will present a very critical situation (extracted from a real game) so that the reader

can be conscious of what, apart from the yield and advantages of the system, he should be

prepared to face if he wants to apply the system without limiting at no time the recovery

progression.

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76 3

77

78

79

80

COMMENTARY OF THE SEQUENCE:

increase more slowly, but the yield, when the recovery is achieved, is inferior.

direct profits and there also more possibilities of appearance of individual groups and of

closing of the recoveries.

recovery without surpassing the limit.

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It is actually an extraordinary situation, as the interval of 15 plays has been multiplied by 5

in plays in which, theoretically, 2 consecutive series of 1 should appear. Can there be a

greater interval? Yes, of course, there is no mathematical rule that prevents it, though one

must admit that the possibilities of appearance are actually minimal.

The possibilities of success increase as the initial capital increases. On the other hand, the

yield of the system has some clear limitations and depends on 2 factors:

when prevailing the long series, the deficit increases more slowly and the yield is

smaller, and vice versa, when short series appear the recovery interval will be shorter,

but the yield higher.

If we make a revision of all the methods and bet systems knows, none can guarantee with

such a low risk such a high percentage of success. The reader who is interested in the topic

can compare, in the book mentioned at the beginning of the chapter, the results to which the

authors arrive starting from the same method (García), with those which obtains our system.

The sequence presented in these pages is clearly prejudicial for our system. Nobody should

make the easy mistake of applying any other system and seeing that it is successful, think

that it has found the definitive solution to the problem. We have to remember that every

system has a favourable situation and an unfavourable one and that we simply have to try

and face the bad one enduring without arriving to the limit, to take advantage and recover

when the situation is good.

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There can be many variations and as always the possible profits are in direct relationship to

the risk that one wants to take.

With the same risk, same yield and the same percentages of success there are the following

options:

1) Attempt the recovery in three bets on the groups of 3 consecutive series of 1 and higher.

Every group should appear every 30 plays. The deficit rises more slowly as we are dividing

it into 3 and the groups of 2 allow us to reduce it in a third part.

2) In a group of 4 consecutive series of 1. There are three groups in total and the appearance

interval is of one every 82 plays. The groups of 2 reduce a fourth part the deficit to recover,

and those of 3 reduce it to the half.

3) In those of 5 we would be waiting for a phenomenon that has a possibility of occurring

every 247 plays, and though the deficit rises very slowly and the inferior groups (2, 3 and 4)

produce a certain relief, we consider that we would be playing too much time under the

pressure of recovery. And we have seen in the case of the group of 2 that the appearance of

the phenomenon (though it is a totally extraordinary situation), can multiply by five the

average interval of appearance.

With a greater risk of capital there can be many options:

1) Bet on the break of the series of 1. When attempting the recoveries we have to add a unit

every time, and the yield increases in a way proportional to the risk of not being able to

2) Lengthen the bet on the series higher than 4.

3) Intensify the bets in the first series (e.g.: 3 units in the series of 1, 2 units in the series of

2 and 1 unit in the remaining series).

The reader will probably need the graphic representation of the possibilities of the system,

but we will not make it, and we will now explain the cause:

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We are very satisfied with the results, obtained from a method which is of difficult practical

application, but yet, these results can be improved.

Can we play in a way yet more intelligent? Of course we can do it and we can manage to

minimise the scarce possibilities that chance has of leaving victorious, but, furthermore we

will have an almost total tranquillity during the game. Our method will come closest to what

it could be called the "infallible" method, and the possibilities of success will be of 98%.

We will now explain this:

The previous method puts all the losses produced by the series of 2, 3 and 4 in a same bank

and attempts to recover them in 2 bets on 2 consecutive series of 1. We have a total of 17

groups of series of 1 that have to recover the deficit caused by the sum of all the series of 2

or higher, what makes in total 31. If we add to this figure all the series of 2 and higher

that prevent us from recovering (63), this means that we are fighting in clear disadvantage

against the BANK. In short sequences with only the appearance of series higher than 1, we

can find that the deficit increases very quickly and exceeds our initial limit. And just after

exceeding ourselves, groups of series of 1 appear that are no longer use to us. We have to

establish a more egalitarian relationship with the BANK. We achieve this by dividing this

deficit in three independent banks (every one will make his own recovery). We explain the

procedure below:

We will bet a unit on the break of the series of 2, 3 and 4. The obtained units are direct

profits.

1??The units lost when appearing a series of 3 will be put inn a bank of losses number 1,

and they will be divided into 3. The chips of the columns 1 and 2 we will attempt to

recover them in 2 consecutive bets with the appearance of a group of 2 consecutive

series of 1 or higher.

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13 5 4 4

5 5 5 8 4 0 4

4 4 4 4 0 0 4

When they appear 2 series of 1 consecutive, in the following play is not bet the figure of the

column number 3. The figure of the column number 3 will be bet only in third play to the

break of the series of 2 (32 series).

When it is lost one of the recovery bets (1, 2 or 3) is added to the deficit and this is returned

to divide between 3.

13 5 4 4

5 5 5 8 4 0 4

4 -4 1 12 4 4 4

4 4 5 8 4 4 0

Possible cases:

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7 3 2 2

3 3 3 4 2 0 2

2 -2 1 6 2 2 2

7 3 2 2

3 3 3 4 2 0 2

2 2 5 2 0 0 2

7 3 2 2

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3 -3 -3 10 4 3 3

3 -3 -6 13 5 4 4

7 3 2 2

3 -3 -3 10 4 3 3

3 3 0 7 4 3 0

4 -4 -4 11 4 4 3

3 -3 -7 14 5 5 4

7 3 2 2

3 3 3 4 2 0 2

2 2 5 2 0 0 2

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2 2 7 0 0 0 0

7 3 2 2

3 3 3 4 2 0 2

2 2 5 2 0 0 2

2 -2 3 4 2 1 1

2??The units lost when appearing a series of 4 will be put in a bank of losses number 2,

they will be divided into 2, and we will attempt to recover them in 2 consecutive bets

with the appearance of a series of 3: when a series of 2 appears, we will play on the

appearance of a series of 3 and we will make the first bet on the continuation of the

series and the following on the break.

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9 5 4

5 5 5 4 4 0

4 4 4 0 0 0

3??The units lost when appearing a series of 5 will be put in a bank of losses number 3,

they will be divided into 2, and we will attempt to recover them in 2 consecutive bets

with the appearance of a series of 4: when a series of 3 appears, we will play on the

appearance of a series of 4 and we will make the first bet on the continuation of the

series and the following on the break.

14 7 7

14 7 7

7 7 7 7 7 0

7 7 7 0 0 0

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Every bank of losses is totally independent of the other and has as objective to close its own

recovery. We recover the losses produced by a series with the appearance of an immediately

inferior one in the cases of the series of 4 and 5, and in the case of those of 3 we continue to

make it with the groups of 2 consecutive series of 1 and 32 series of 2

With 49 valid groups we attempt to recover the losses produced by sixteen series of 3, two

of 6 , one of 7 and the ones produced by the 31 series higher to 2 when failing the first

recovery bet (increases in 1/2 the deficit).

With 16 groups we attempt to recover the losses produced by eight series of 4, two of 6, one

of 7 and the ones produced by the thirty-two series of 2 when failing the first recovery bet

(increases in 1/2 the deficit).

With 8 valid groups we attempt to recover the losses produced by four series of 5, two of 6,

one of 7 and the ones produced by the sixteen series of 3 when failing the first recovery bet

(increases in 1/2 the deficit).

We have improved a lot but as it is not still enough, since we have a recovery bank (number

1) which gives too many facilities to the BANK and in an really critical situation it would

take us beyond our initial limit. We know also, thanks to the analysis of thousands of

plays of roulette that, when a given phenomenon does not want to appear, little can traditional methods

do. We will put an example: we can have 0 in the banks number 1 and 3 and an average

deficit in the number 2. So we would only need a series of 3 to cancel it (a series of 3

should appear regularly once every 15 plays, but we have already seen that this theoretical

interval can be multiplied by 5 in practice). In these moments, during 50 plays, we see the

appearance of a sequence (that it may be only once in 1000 plays, but when it happens

makes our method useless), with many series of 1 and 2 chained with series of 4 and higher

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that make the deficit of bank number 2 quickly exceed our limit. Our predictions based on

the calculation of probabilities will be of no use.

How to solve the problem? The solution is given to us by chance itself: when a given

phenomenon does not appear, it means that others are appearing. When a series of 3 does

not appear, others must appear (1, 2, 4, 5, etc.). This is the key to the problem, to avoid that

the absence of a given phenomenon should be solved with this same phenomenon. If we

can make the absence of a given phenomenon be solved, at least in part, by 2 different ones,

we will avoid in a 98% of occasions the collapse of the strategy. We do not like using the

term 100%, since we know that a situation which has not appeared in 10000 plays can

present itself in the least unexpected moment, but, when we finish to explain the system, all

the readers will have to agree with us that this is the method that comes closer to the term

"infallible", if it can not, in fact, be called this way.

What it is certain is that you will be prepared to endure really critical situations that no other

method could resist, finally recovering all the losses and obtaining a yield more than

acceptable. To all this we have to add the fact that the investment of capital that we need to

put it into practice is really low.

How can we make the the absence of a phenomenon be solved by the appearance of others

opposed? When a recovery bet fails and it is equal or higher than 3 units, instead of adding

it completely to our own bank, it will be distributed into 3 banks.

Ex: We have in bank number 2 a deficit of 9 units ( there appear series of 2, of 4 and higher

and none of 3). The first recovery of 5 fails. Instead of adding it totally to bank number 2

which would make a total of - 14, we divide it into 3 (2, 2 and 1). We add the first 2 units

to the previous 9 getting a total of 11, the 2 following units are added to bank number 1 and

the remaining unit in bank number 3. We are avoiding that the absence of series of 3

increases the deficit in bank number 2 and at the same time we may obtain a series of 4 or 2

series of 1 consecutive that make us reduce the deficit in one or two thirds .

IMPORTANT: The division between the 3 banks only will be effected when it will be the

first recovery bet (column 1 of the banks 1, 2 i 3) and when we effect the only one recovery

of the column 3 of the bank number 1. Motive: When it is tried to the second recovery, it

will not alter the original deficit of this bank and there has not of altering the deficit of the

others banks.

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4 2 1 1 9 5 4 3 2 1

5 -5 6 2 2 2 11 6 5 4 2 2

4 2 1 1 9 5 4 3 2 1

5 5 4 2 1 1 4 4 0 3 2 1

4 -4 4 2 1 1 8 4 4 3 2 1

A very important detail, when the failed recovery bet is divided into 3, the first part is added

to corresponding bank, and the following two are added to the remaining banks from left to

right. This rule has an only exception when the deficit surpasses 15 units. As a precaution

against the persistence of the situation, we will add to this bank the smaller part and the

remaining two will be put in the same way from left to right in the remaining banks.

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19 7 6 6 6 3 3 3 2 1

7 -7 21 7 7 7 9 5 4 5 3 2

In the case of 2 banks exceeding 15 units, we will follow the priority from left to right and

the remaining quantity will be put in the last. And in the totally unlikely fact that 3 banks

exceeded 15 units we will follow the initial procedure.

16 6 5 5 20 10 10 7 4 3

10 -10 19 7 6 6 23 12 11 11 6 5

We have of taking advantage also the greater appearance of the one phenomena and the

closes to zero or important decrease of the deficit of the corresponding bank, to get lighter

the deficit of the others 2 banks. We establish a maximum deficit and closing figure for

every one of the banks:

DEFICIT CLOSING

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When one of the banks closes, if the others banks even or surpass the indicated figure, their

deficit will be divided with the bank that there has closed. We will put 3 examples:

BANK NUMBER 1 remain with an inferior deficit to 5 units. The bank number 2 super 10

units. The bank number 2 divides its deficit with the bank number 1.

DÉFICITS BEFORE DEFICITS AFTER

BANK NUMBER 3: 4 4

BANK NUMBER 2 remain with an inferior deficit to 4 units. The banks numbers 1 and 3

divide their deficit with the bank number 2.

DEFICITS BEFORE DEFICITS AFTER

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BANK NUMBER 3 closes to 0. The bank number 2 divides his déficit with the bank

number 3

DEFICITS BEFORE DEFICITS AFTER

15 5 5 5 9 5 4 2 1 1

1 1 1 18 6 6 6 6 3 3 3 2 1

1 1 1 11 4 4 3 10 5 5 5 3 2

The balance between the different deficits is important so that the bets are not increased

quickly when one of the phenomena delays his appearance. For so much, always exist the

conditions of the values of LIMIT and CLOSE we can to do the operations explained

previously.

We will play as there were 3 different players, but mutually helping them in critical

situations. The first player attempts to obtain as net profits the chips produced by the series

of 2, the second player makes the same with the series of three and the third player with the

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series of 4.

number 1.

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of the series, an only recovery bet of the column number 3 of the bank 1, and at the same

time a first recovery bet of bank number 2.

the intermittence, a second recovery bet of bank number 2 and the first recovery bet of

bank number 3.

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intermittence and the second recovery bet of bank number 3.

As we can see, in 3 plays we will make opposed roulette bets but we have to see the procedure

followed by each bank as a totally independent process that has an only purpose: to obtain,

on the one hand, a greater resistance against adverse situations and besides net profits

consisting in the sum of all the units bet on the break of the series of 2, of 3 and of 4.

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The real bet will be the result of adding or subtracting the different bets. It is easy to

understand that, unlike the previous method, in this we will normally have some recoveries

still to be closed, but it is also possible to close them all with a given sequence (series in

diminishing order: 4 - 3- 1 - 1 or other sequences that would leave us a minimal deficit in

some of the banks). The most remarkable fact is the calmness that it gives us during the

game and the great resistance that is obtained by having the deficit divided into 3 and being

able to ease the bank that causes us more strategy problems.

The only defect of the system is its relative complexity as we have to make so many

operations in the same play, but this complexity reduces with practice. For all systems it is

advisable to make many tests before playing with real money, in this we emphasise the

importance of assimilating well the mechanism so that you make all the operations in an

automatic way and you can perfectly control the game

A last point: Appearance of the zero. Until the moment we thought unnecessary risking to

recover the losses produced by its appearance, but after all the tests made and relying on the

greater resistance that has the method, we will let it to the election of the player. The

procedure to follow when it appeared would be to divide the losses into 3 and add it to the

banks, but from right to left, because of the reason previously explained (ex: BET: 8.

LOSS: 4. ORDER: 1, 1, 2).

We will work on the sequence of the graphics 19 and 20, a very critical sequence, so that

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the results can be compared and to demonstrate the theory explained so far.

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respective banks. As there is no previous deficit, we make only one bet.

number 8.

appeared a zero. We repeat the bet, we added a unit to the bank number 1, and we reflect

the loss in the PROFITS column.

We also make the first recovery bet of bank number 2 on a series of 3 and we bet a unit on

the intermittence. In this case the real bet is 1.

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to the bank number 1.

first recovery of bank number 3 and we bet a chip on the intermittence. The real bet is the

result of adding the chips bet on the intermittence and on the break of the series of 3 (bank

number 2) minus the bet made on the continuation of the series (bank number 3).

intermittence. This lost chip goes to bank number 2.

the intermittence. The real bet is the sum of these two bets.

units. It is not distributed between 3 banks.

units. It is distributed between 3 banks.

are added and distributed. The same fact occurs in the plays 51 and 53.

lost the chip bet on the intermittence. Observe that the result is -3 and the deficit in this

bank goes from 2 to 5 units.

on 10 units (- 20) in bank number 3. We divide it with bank number 2, so that the two banks

have a deficit of 10 units. Bank number 1 continues unalterable.

time the chip bet to the intermittence and lost is added to the bank number 2.

the banks 1 and 2 super theirs limits and continue inalterable.

We end the sequence with a deficit of - 2 chips. We still have to recover 9 units of the bank

number 1 and 9 of the bank number 2.. It would make a total of 16 chips that are the 16

series of 2, 3 and 4 appeared.

This is a very unfavorable sequence for the system (with clear dominance of the large series

on the shorts) and no matter what it end with losses. What imports actually it is to know

how resisting it when is presented, for to can win after with the "normal" sequences.

Everybody knows to win in the favorable situations, but well few know to make it in the

unfavorable. At any rate we will present a short sequence of 40 spins more current in the

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game table and we will see clearly which is the yield that can obtain the roulette strategy with

alternated gambling (graphic 45).

GRAPHICS 19 And 20 GRAPHICS 43 And 44

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1) In alternation situations of all the series it will go on closing the different recoveries and

obtaining profits.

2) In critical situations it avoids the collapse by preventing the rapid increase of problematic

deficits by dividing the highest bets into the three banks and making that always one of

them closes the recovery.

3) The maximum risked quantity has been of 34 units. Normally we would begin the game

with 50 units, therefore, we would be yet far from the limit.

4) This sequence can appear but rarely. Normally, the game is very changing (with

alternation of all kinds of series) what has always made very difficult to apply an effective

method for all kinds of situations. And one must recall that at the end of 250 plays, the

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distribution of the series will have come closer to the one which we know as ideal.

Logically, after this sequence there will come another totally different that will take us back

to void deficits or totally non-existent and the profits will be put on the same level with the

total of similar series of 2, 3 and 4.

5) We achieve a great resistance to overcome the most adverse situations.

6) The necessary initial capital is low. With 50 chips we cover sufficiently any critical

situation.

7) The method gives a great confidence because we know that sooner or later we will close

some of the banks and if there is some indeed problematic one, we will be able to ease it.

8) Our position is much more comfortable. Unlike before we do not have to rely on the

appearance of an only phenomenon to close the recovery. When this did not happen or took

much time it appear, we could ourselves compelled to abandon the game having lost all the

initial capital. Now we have 3 different options and each one collaborates with the others.

9) The losses caused by the zero can be recovered. A possible option is to wait until they

add up to 3 units and to distribute them into 3 banks. There are other options, but we leave

them to the player’s imagination. The only thing will be to add a column next to zero, in

which we control the total of these losses.

series. The chips wined go directly to profits. The lost chips will be put on the bank 1 or

2 (the one which has a smaller deficit), never in bank 3.

Depending on the class of game, at the end of the session of 250 spins it can suppose some

profits of 40 chips more, but the risk is greater.

be greater.

In any case the player can choose between not to bet (and take advantage to be relaxed) or

to follow the previous procedure.

1) RECOVERY OF LOSSES BETWEEN 3 INDEPENDENT BANKS

2) DIVISION OF THE LOSSES SUPERIOR TO 3 UNITS BETWEEN 3 BANKS.

3) DECREASE OF THE DEFICITS MORE PROBLEMATIC WHEN A BANK CLOSES

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TO ZERO OR REMAIN WITH A DEFICIT VERY LOW.

1) Not recovering the losses caused by the zero: 50 - 60 chips.

2) Recovering the losses caused by the zero: 55 - 65 chips.

In this method we can speak of team game but with only one player. The only defect it has

(the advantages we have already seen) is the great concentration that demands on the player

at all times, and the fact of having to make until four different operations.

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Playing in this way the game is simplified much. In any case we believe that is worth the

trouble to make many tests until perfectly assimilating the mechanism, obtaining the

necessary agility. Roulette players know that a method that guarantees such a high

percentage of success in ALL the situations could not have a relatively easy application. If

someone believes that its application is too complex, he always has simpler options

previously explained in these pages, but they will not guarantee the same results. We limit

ourselves to explain how to play in the most intelligent possible way and we wanted to

demonstrate than the set phrase heard so many times since this game was invented - THE

BANK ALWAYS WINS - is not true.

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